Problem: 1502. 判断能否形成等差数列 Can Make Arithmetic Progression From Sequence耗时100内存100等差数列一定是排好序的所以排序以后查看相邻数字差是否相同即可Codeclass Solution { public: bool canMakeArithmeticProgression(vectorint arr) { sort(arr.begin(), arr.end()); int d arr[1] - arr[0]; int n arr.size(); for(int i 2; i n; i) { if(arr[i] - arr[i-1] ! d) return false; } return true; } }; leetcode 耗时100内存100 1502. 判断能否形成等差数列 Can Make Arithmetic Progression From Sequence
Problem: 1502. 判断能否形成等差数列 Can Make Arithmetic Progression From Sequence耗时100内存100等差数列一定是排好序的所以排序以后查看相邻数字差是否相同即可Codeclass Solution { public: bool canMakeArithmeticProgression(vectorint arr) { sort(arr.begin(), arr.end()); int d arr[1] - arr[0]; int n arr.size(); for(int i 2; i n; i) { if(arr[i] - arr[i-1] ! d) return false; } return true; } };